| Force $\vec F = k \frac{Qq}{r^2} \hat a _r [=] N$ | Field $|\vec E| = k\frac{Q}{r^2} \hat a_r$ | $\vec E = \frac{\vec F}{q}$ | | --- | --- | --- | | Electrostatic Potential Energy (U) $U = k \frac{Qq}{r}$ | Electric Potential (Voltage) $V = k\frac{Q}{r}$ | $V = \frac{U}{q}$ |

<aside> ⚙ The force on charge $q_0$ (we take $q_0$ to be positive here) due to the charge $q$ is given by $|\overrightarrow{F_{q_0,q}}| = k \frac{|q_0||q|}{r^2}$

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Calculating Coulomb’s Law