Rate of voltage change depends on the current and capacitance
$$ I = C \frac{dV}{dt} $$
For a falling output transition, input steps from 0 → $V_{DD}$, where $I_{dn1}$ is the nMOS transistor current, which depends on the operating region of linear or saturation
$$ C_{out} \frac{dV_B}{dt} = -I_{dn1} $$
$$ \frac{dV_B}{dt} = -\frac{\beta}{C_{out}} \cdot \frac{(V_{DD} - V_t)^2}{2} \quad \text{(Saturation)} $$
$$ \frac{dV_B}{dt} = -\frac{\beta}{C_{out}} \left(V_{DD} - V_t - \frac{V_B}{2}\right) V_B \quad \text{(Linear)} $$
Inverter ramp response
